may-17-2004 1 bcr179.../semb4 pnp silicon digital transistor ? switching circuit, inverter, interface circuit, driver circuit. ? built in bias resistor ( r 1 = 10k ? ) ? for 6-pin packages: two (galvanic) internal isolated transistors with good matching in one package bcr179f/l3 bcr179t semb4 eha07180 3 12 be c 1 r eha07266 6 54 3 2 1 c1 b2 e2 c2 b1 e1 tr1 tr2 r 1 r 1 type marking pin configuration package bcr179f BCR179L3 bcr179t semb4 wws ww wws ww 1=b 1=b 1=b 1=e1 2=e 2=e 2=e 2=b1 3=c 3=c 3=c 3=c2 - - - 4=e2 - - - 5=b2 - - - 6=c1 tsfp-3 tslp-3-4 sc75 sot666
may-17-2004 2 bcr179.../semb4 maximum ratings parameter symbol value unit collector-emitter voltage v ceo 50 v collector-base voltage v cbo 50 emitter-base voltage v ebo 5 input on voltage v i(on) 20 collector current i c 100 ma total power dissipation bcr179f, t s 128c BCR179L3, t s 135c bcr179t, t s 109c semb4, t s 75c p tot 250 250 250 250 mw junction temperature t j 150 c storage temperature t stg 150 ... -65 thermal resistance parameter symbol value unit junction - soldering point 1) bcr179f BCR179L3 bcr179t semb4 r thjs 90 60 109 300 k/w 1 for calculation of r thja please refer to application note thermal resistance
may-17-2004 3 bcr179.../semb4 electrical characteristics at t a = 25c, unless otherwise specified parameter symbol values unit min. typ. max. dc characteristics collector-emitter breakdown voltage i c = 100 a, i b = 0 v (br)ceo 50 - - v collector-base breakdown voltage i c = 10 a, i e = 0 v (br)cbo 50 - - emitter-base breakdown voltage i e = 10 a, i c = 0 v (br)ebo 5 - - collector-base cutoff current v cb = 40 v, i e = 0 i cbo - - 100 na dc current gain 1) i c = 5 ma, v ce = 5 v h fe 120 - 630 - collector-emitter saturation voltage 1) i c = 10 ma, i b = 0,5 ma v cesat - - 0,3 v input off voltage i c = 100 c, v ce = 5 v v i(off) 0,4 - 1 input on voltage i c = 2 ma, v ce = 0,3 v v i(on) 0,5 - 1,1 input resistor r 1 7 10 13 k ? ac characteristics transition frequency i c = 10 ma, v ce = 5 v, f = 100 mhz f t - 150 - mhz collector-base capacitance v cb = 10 v, f = 1 mhz c cb - 1,2 - pf 1 pulse test: t < 300s; d < 2%
may-17-2004 4 bcr179.../semb4 dc current gain h fe = ? ( i c ) v ce = 5 v (common emitter configuration) 10 -4 10 -3 10 -2 10 -1 a i c 1 10 2 10 3 10 h fe collector-emitter saturation voltage v cesat = ? ( i c ), h fe = 20 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 v 1 v cesat -4 10 -3 10 -2 10 -1 10 a i c input on voltage v i (on) = ? ( i c ) v ce = 0.3v (common emitter configuration) 10 -1 10 0 10 1 10 2 v v i(on) -4 10 -3 10 -2 10 -1 10 a i c input off voltage v i(off) = ? ( i c ) v ce = 5v (common emitter configuration) 0 0.5 1 v 2 v i(off) -6 10 -5 10 -4 10 -3 10 -2 10 a i c
may-17-2004 5 bcr179.../semb4 total power dissipation p tot = ? ( t s ) bcr179f 0 20 40 60 80 100 120 c 150 t s 0 50 100 150 200 mw 300 p tot total power dissipation p tot = ? ( t s ) BCR179L3 0 20 40 60 80 100 120 c 150 t s 0 50 100 150 200 mw 300 p tot total power dissipation p tot = ? ( t s ) bcr179t 0 20 40 60 80 100 120 c 150 t s 0 50 100 150 200 mw 300 p tot total power dissipation p tot = ? ( t s ) semb4 0 20 40 60 80 100 120 c 150 t s 0 50 100 150 200 mw 300 p tot
may-17-2004 6 bcr179.../semb4 permissible pulse load p totmax / p totdc = ? ( t p ) bcr179f 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p 0 10 1 10 2 10 3 10 p totmax / p totdc d=0 0.005 0.01 0.02 0.05 0.1 0.2 0.5 permissible puls load r thjs = ? ( t p ) bcr179f 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p -1 10 0 10 1 10 2 10 k/w r thjs d=0.5 0.2 0.1 0.05 0.02 0.01 0.005 0 permissible puls load r thjs = ? ( t p ) BCR179L3 10 -7 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p -1 10 0 10 1 10 2 10 r thjs 0.5 0.2 0.1 0.05 0.02 0.01 0.005 d = 0 permissible pulse load p totmax / p totdc = ? ( t p ) BCR179L3 10 -7 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p 0 10 1 10 2 10 3 10 p totmax / p totdc d = 0 0.005 0.01 0.02 0.05 0.1 0.2 0.5
may-17-2004 7 bcr179.../semb4 permissible puls load r thjs = ? ( t p ) bcr179t 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p -1 10 0 10 1 10 2 10 3 10 k/w r thjs d=0.5 0.2 0.1 0.05 0.02 0.01 0.005 0 permissible pulse load p totmax / p totdc = ? ( t p ) bcr179t 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p 0 10 1 10 2 10 3 10 p totmax / p totdc d=0 0.005 0.01 0.02 0.05 0.1 0.2 0.5 permissible puls load r thjs = ? ( t p ) semb4 10 -7 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p -1 10 0 10 1 10 2 10 3 10 k/w r thjs 0.5 0.2 0.1 0.05 0.02 0.01 0.005 d = 0 permissible pulse load p totmax / p totdc = ? ( t p ) semb4 10 -7 10 -6 10 -5 10 -4 10 -3 10 -2 10 0 s t p 0 10 1 10 2 10 3 10 p totmax / p totdc d = 0 0.005 0.01 0.02 0.05 0.1 0.2 0.5
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